there are only 2 solutions: 78981/101547 and 79191/101817.-michael marfil I think your puzzle has the solution… SEVEN = 78981 NINTHS = 101547 Also, see http://users.aol.com/s6sj7gt/mikealp.htm for Mike Keith's alphametics page – taking them to the extreme. There are some truly (perhaps maximally) dense puzzles there. Regards Mark Michell The first double true of this kind I know was by Jesus Sanz and was send to the spanish puzzle list Snark some monthes ago, maybe more, was: Cripto Fraccion 1: (Jesus Sanz) TRES/OCHO = 3/8 Then I found: Cripto Fraccion 2: TRES/NUEVE = 3/9 sin usar el 0. 4562/13686 Cripto Fraccion 3: CUATRO/VEINTE = 4/20 170469/852345 Cripto Fraccion 4: CINCO/TRECE = 5/13 30435/79131 Cripto Fraccion 5: SEIS/DIEZ = 6/10 4914/8190 Cripto Fraccion 6: SEIS/TRECE = 6/13 6876/14898 Cripto Fraccion 7: SIETE/TRECE = 7/13 17535/32565 Cripto Fraccion 8: DIEZ/TRECE = 10/13 9650/12545 Cripto Fraccion 9: (UNO+SIETE)/CINCO = 8/5 670+54898/34730 Cripto Fraccion 10: (DOS+NUEVE)/CINCO = 11/5 357+64818/29625 Cripto Fraccion 11: (TRES+TRECE)/CINCO = 16/5 8473+84727/29125 Cripto Fraccion 12: (SEIS+QUINCE)/CINCO = 21/5 9389+278563/68560 I also found this kind of problem/solution in English but I cannot find now. My daughter has 1 and 1/2 year, no time for puzzles! Best wishes, Rodolfo Kurchan Dear Sir, E = 8, H = 4, I = 0, N = 1, S = 7, T = 5, V = 9 SEVEN = 78981 NINTHS = 101547 SEVEN/NINTHS = 78981/101547 = 7/9 Regards, Veo Chau Seven 78981 Ninths 101547 Neil Jones Bryce problem 7/9 = 78981/101547. Regards Eswaran Narasimhan Hi Ed, I solved Bryce Herdt's proportion: SEVEN/NINTHS=7/9 78981/101547=7/9 or {S=7, E=8, V=9, N=1, I=0, T=5, H=4} Solution strategy (since I like to see people's methods): (1) 7x < 100,000 and 9x >= 100,000 (given number of letters) (2) 11,111 < x < 14,285 (from 1) (3) N=1 (since 9x < 128,565 from 2) (4) 11,248 < x < 13,555 (since 101,234 < 9x < 121,987 from 3) (5) S=7 (since 7x ends in 1 --> x ends in 3 --> 9x ends in 7) (6) 78,736 < 7x < 79,996 (from 4,5) (7) 78,771 < 7x < 79,961 (from 3,6) (8) SEVEN = 78,981 or SEVEN = 79,891 (by scrolling through all seventeen possible cases of 78,771 + 70n < 79,961 on a calculator and noting the two cases where E=E) (9)SEVEN = 78,981 (since 79,891*(9/7)=102,717 NINTHS) and NINTHS = 101,547 - Matt Sheppeck This is my solution to the SEVEN/NINTHS problem by Michael Trigiani I did this problem by hand with some trial and error. 7x = SEVEN and 9x = NINTHS I found the lower and upper bound for x. The upper bound is found by 98784/7 = 14112 (98784 is the highest possible number SEVEN could be divisible by 7). The lower bound is found by 101259/9 = 11251 (101259 is the smallest possible number NINTHS could be divisible by 9). Therefore the range that x could be is 11251-14112. 14112*9 would give the range that NINTHS could be, which is 127008. This tells us that N=1, which also tells us that the ones digit in x is 3, and also tells us that S=7 7x = 7EVE1 and 9x = 1I1TH7 I know found a new upper and lower bound for x. The upper bound is found by 79891/7 = 11413 (79891 is the highest possible number SEVEN could be divisible by 7). The lower bound is found by 70301/7 = 10043 (70301 is the smallest possible number SEVEN could be divisible by 7). Therefore the range that x could be is 10043-11413. 11413*9=102717 which shows that I=0. 7x = 7EVE1 and 9x = 101TH7 Because 1+0+1+7=9, then the sum of T+H must be a multiple of 9. The only possible choices for NINTHS at this point would be (101367, 101457, 101547, 101637). Dividing each of these choices by 9 would in the possibilities of what x is. (101367/9=11263, 101457/9=11273, 101547/9=11283, 10163/9=11293). Using these possibilities for x and multiplying them with 7 will determine the value of SEVEN (11263*7=78841, 11273*7=78911, 11283*7=78981, 11293*7=79051). SEVEN=78981, NINTHS=101547, SEVEN/NINTHS=78981/101547=7/9 seven/ninths = 78981/101547 Jeff Smith Hi Ed, 78981/101547 fits the bill. Regards, Mike Shafer